Given a tetrahedron of reference ABCD, let λ, μ, ν, π be the cosines of the angles made by a line with the perpendiculars to the faces BCD, ACD, ABD, ABC respectively, these perpendiculars being drawn all inwards or all outwards; where
Aλ 1 + Bμ 1 + C½ 1 + Dπ 1 = 0
Aλ 2 + Bμ 2 + C½ 2 + Dπ 2 = 0
A, B, C, D being the areas of the faces BCD, .. If P 1 (α 1, ² 1, γ 1, δ 1) and P 2 (α 2, β 2, γ 2, δ 2) are any two points, the lines PP 1 and PP 2 can be written
(α - α 1)/λ 1 = (β - β 1)/μ 1 = (γ - γ 1)/ν 1 = (δ - δ 1)/π 1 = θ 1,
(α - α 2)/λ 2 = (β - β 2)/μ 2 = (γ - γ 2)/ν 2 = (δ - δ 2)/π 2 = θ 2,
to find the cosine of the angle between PP 1 and PP 2.