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Published online by Cambridge University Press: 14 March 2022
Let p be a prime with $p\equiv 1\pmod {4}$. Gauss first proved that
$2$ is a quartic residue modulo p if and only if
$p=x^2+64y^2$ for some
$x,y\in \Bbb Z$ and various expressions for the quartic residue symbol
$(\frac {2}{p})_4$ are known. We give a new characterisation via a permutation, the sign of which is determined by
$(\frac {2}{p})_4$. The permutation is induced by the rule
$x \mapsto y-x$ on the
$(p-1)/4$ solutions
$(x,y)$ to
$x^2+y^2\equiv 0 \pmod {p}$ satisfying
$1\leq x < y \leq (p-1)/2$.
The first author is supported by the National Natural Science Foundation of China (Grant No.11971222). The second author is supported by the National Natural Science Foundation of China (Grant No.12071208).